2019-2-14 mysql通过时间判断七天出现的次数统计

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select a.date_list,ifnull(b.count,0) as count
from (
select curdate() as date_list
union all
select date_sub(curdate(),interval 1 day) as date_list
union all
select date_sub(curdate(),interval 2 day) as date_list
union all
select date_sub(curdate(),interval 3 day) as date_list
union all
select date_sub(curdate(),interval 4 day) as date_list
union all
select date_sub(curdate(),interval 5 day) as date_list
union all
select date_sub(curdate(),interval 6 day) as date_list
) as a left join (
select date(gmt_create) as datetime,count(*) as count from alarm_message where student_status = "OUT_OF_SCHOOL"
group by date(gmt_create)
) as b on a.date_list = b.datetime

https://blog.csdn.net/ouyang111222/article/details/77638826